(3x+2)(2x^2-5x-3)=0

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Solution for (3x+2)(2x^2-5x-3)=0 equation: 


Simplifying
(3x + 2)(2x2 + -5x + -3) = 0

Reorder the terms:
(2 + 3x)(2x2 + -5x + -3) = 0

Reorder the terms:
(2 + 3x)(-3 + -5x + 2x2) = 0

Multiply (2 + 3x) * (-3 + -5x + 2x2)
(2(-3 + -5x + 2x2) + 3x * (-3 + -5x + 2x2)) = 0
((-3 * 2 + -5x * 2 + 2x2 * 2) + 3x * (-3 + -5x + 2x2)) = 0
((-6 + -10x + 4x2) + 3x * (-3 + -5x + 2x2)) = 0
(-6 + -10x + 4x2 + (-3 * 3x + -5x * 3x + 2x2 * 3x)) = 0
(-6 + -10x + 4x2 + (-9x + -15x2 + 6x3)) = 0

Reorder the terms:
(-6 + -10x + -9x + 4x2 + -15x2 + 6x3) = 0

Combine like terms: -10x + -9x = -19x
(-6 + -19x + 4x2 + -15x2 + 6x3) = 0

Combine like terms: 4x2 + -15x2 = -11x2
(-6 + -19x + -11x2 + 6x3) = 0

Solving
-6 + -19x + -11x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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